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by btilly
2104 days ago
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Each tail is bounded above by e^(x^2/2) / (x sqrt(2 pi)). Take logs and you get (x^2 / 2) - log(x) - log(2 pi)/2. Calculate that out and you get to about 1.44 * 10^85. You can double that for 2 tails. But it is still an impressively small number. |
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