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by edflsafoiewq 2119 days ago
Depends how you use it (&a[3], sizeof(a[3])). But its type is still char.
1 comments
richardwhiuk 2110 days ago
IIRC, both of those are undefined.
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edflsafoiewq 2103 days ago
&a[3] is allowed, it's a one-past-the-end-of-the-array pointer. &a[4] would be UB (if it were evaluated).

sizeof(a[3]) is not evaluating a[3], so it also isn't UB.

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