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by GuB-42
2107 days ago
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I usually do the "inMeters" thing. Another thing you can do is define a "METER" constant equal to 1. You can then call your function like this: func(1.5 * METER), and when you need a number of meters, you can do "accuracy / METER". The multiplication and division should be optimized away. Good thing about that is that you can specify the units you want, for example you can set FOOT to 0.3048 and do "5. * FOOT" and get back your result in centimeters by doing "accuracy / CENTIMETER". The last conversion is not free if the internal representation is in meter but at least, you can do it and it is readable. If you are going to use such distances a lot, at least in C++, you can get a bit of help from the type system. Define a "distance" class operator overloads, constants and convenience functions to enforce consistent units. Again, the optimizer should make it not more costly than using raw floats if that's what you decide to use as an internal representation. |
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