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by dependenttypes 2135 days ago
doing simply funname(args): would work fine
1 comments

How would the parser know that’s a function definition and not a function call?
by the :
That's too late. The parser needs to know whether it's looking at a definition or a call before that - for example, to know whether to parse "args" as a `parameters` or an `arglist` [0].

[0] https://docs.python.org/3/reference/grammar.html