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by hilbertseries
2138 days ago
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You are wrong. Godel in fact showed precisely that there are unprovable statements in any consistent set of axioms. In fact it’s equivalent. The only systems in which every statement is provable are inconsistent. Consistent here meaning that statements cannot be proven to be both true and false from axioms. |
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1. The theory must be strong enough to do a certain amount of arithmetic
2. The axioms of the theory must be computably enumerable
So, you can have relatively weak theories in which the incompleteness results don't hold. A major example here is comes from Gödel's _completeness_ theorem (notice "completeness" not "INcompleteness") which says: in first-order logic a statement is true if and only if its provable.
You can also have strong theories whose axioms are not computably enumerable. Start with something like the Peano axioms and consider the set of all true statements in that theory. We can take any set we want as axioms, so what if we take the set of all true statements in Peano arithmetic as our axioms?
Now every valid "proof" is one line long since what was previous a theorem is now an axiom, but we've kicked the can down the road. How do we figure out whether something is an axiom in this new system or not?
This latter system is called "true arithmetic" Gödel's incompleteness theorems don't apply there, either.