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by kgm 2150 days ago
I am seeing other analyses that put the size of the explosion at about one tenth of this size.

The analysis in this Twitter thread correlates the observed degree of damage with the distance from the explosion. It comes up with an estimated 240 tons TNT-equivalent, though naturally this comes with a considerable margin of error.

https://twitter.com/GeorgeWHerbert/status/129071971954515968...

This Twitter thread is making the point that the explosiveness of ammonium nitrate can vary significantly depending on how it is stored. 2750 tons of AN at 20% efficiency gives 550 tons TNT.

https://twitter.com/ArmsControlWonk/status/12907955327014256...

This range is also apparently consistent with the explosion registering as a 3.5 seismic magnitude.

https://twitter.com/ArmsControlWonk/status/12907348507695267...

There are still a great many unknowns, and none of this should be mistaken for the real analysis which will come later, but these disparate sources of information all seem to agree with each other, to a first approximation.

6 comments

My fluid mechanics prof told the class that a scientist in the 1940's published the yield of the Hiroshima bomb. Since this was top secret, he got investigated. But he showed how the yield could be calculated from the film of the explosion - how fast the blast radius expanded.

So I imagine the yield of the Beirut explosion could be calculated the same way from the video.

Paper in question.

http://sites.science.oregonstate.edu/~restrepo/MTH481/Classn...

From videos:

R=450m

t=1.5s

rho=1.2kg/m3

E=9.84E12 kg.m2/s2 or 9.84E19 erg

Equiv TNT = 2.5kTonnes -TNT

Equiv AN = 5400 Tonnes

So double what current media is saying.

edit:formatting.

You have to be careful about your errors though with this method, because you get higher-order powers. If the radius estimation was wrong by only 10%, your final answer will be wrong by almost 50%.
You da man! Thank you.
It was G.I. Taylor.
Using the Buckingham Pi theorem.
And data from smaller explosions of known magnitude, in order to determine the dimensionless constant that cannot be determined from Buckingham’s theorem alone.
There's a story about Feynman estimating yield by dropping pieces of paper and seeing how far they'd travel in the shockwave
Feynman told that story about Fermi.
Imagine being so good that Feynman tells stories about you (rather than himself).

Fermi also put Dyson down gently once "A successful theory must have either a strong physical intuition or a rigorous mathematical basis: you have neither"

Fermi was an inveterate experimentalist, always trying to measure and test things. Hence the idea of the Fermi estimate.

There's a good piece about him here: https://www.lrb.co.uk/the-paper/v40/n10/steven-shapin/think-...

>Fermi saw the Trinity Test as an opportunity for one of his famous exercises of rational estimation, a Fermi problem. First, he offered to take wagers from other scientists on whether the bomb would ignite the atmosphere, destroying New Mexico or even the entire world. Then, the evening before, he carefully prepared an experiment to estimate the bomb’s explosive yield:

> "About forty seconds after the explosion the air blast reached me, I tried to estimate its strength by dropping from about six feet small pieces of paper before, during and after the passage of the blast wave. Since, at the time, there was no wind, I could observe very distinctly and actually measure the displacement of the pieces of paper that were in the process of falling while the blast was passing. The shift was about 2.5 metres, which, at the time, I estimated to correspond to a blast that would be produced by ten thousand tons of TNT."

> "He was so profoundly and totally absorbed in his bits of paper," his wife recorded, "that he was not aware of the tremendous noise." The answer later calculated by the instrumentation specialists was 18 kilotons, but Fermi’s answer was arrived at on the spot – and it was correct within an order of magnitude.

> First, he offered to take wagers from other scientists on whether the bomb would ignite the atmosphere, destroying New Mexico or even the entire world.

Of course if you bet on the bomb not causing the end of the world, you can only win.

Ah you're right!
I went on Nukemap and twiddled the yield until the radius of overpressure damage roughly matched the damage seen in the footage.

I arrived at 0.25 +/- 0.1 kT before the 2750T figure came out. That's in line with TNT-equivalent efficiency of AN and incomplete reaction due to scattering.

Tragically, this suggests a much higher death toll than currently reported. I am not sure if nukemap factors local population density; fortunately the epicenter was a sparsely populated pier.

(down for me right now, I bet their site is slashdotted/DoS'd by people doing similar) https://nuclearsecrecy.com/nukemap/classic/

2750 tons of AN perfectly mixed to make ANFO only gets you 2.2kt. So unless if the actual amount of AN was higher, or something else detonated with it, 2.2kt is probably our theoretical ceiling.
Damage estimates in some cases may underrate the explosion because that grain elevator which remarkably remained largely upright seems to have acted like a huge sandbag, subtending an angle so large as to shield the heart of the city of Beirut from the worst ravages of the blast.
an expert's thread from this morning: https://twitter.com/johnismay/status/1290858204788924416
Yes, thanks for the correction!
> I am seeing other analyses that put the size of the explosion at about one tenth of this size.

Random twitter users are guesstimating from smartphones videos and have 0 knowledge of the actual location, so yeah, it's just guesstimates. I'm still wondering why people do that, it's kind of a weird flex and bring literally nothing of value to the table besides trying to sound like a smartass.

Some of those are involved in the OSINT community where they do this as their day job, because analysing random strange explosions can sometimes tell you things about military weapons development programs that aren't otherwise advertised.