[nine_k]

I can't get it, and from my experience, this is not true.

Consider:

  const x = await foo();
  await bar(x);

How can you schedule `foo()` and `bar()` in parallel, when they have an explicit data dependency?

[recursive]

> How can you schedule `foo()` and `bar()` in parallel, when they have an explicit data dependency?

You can't, but that's a fundamentally different scenario than what's being discussed.