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by xvilka 2166 days ago
Rust is well designed modern and concise language with sound type system, while C++ isn't. The difference is huge and obvious.
3 comments

Except that one of Linus' most vocal offenses on C++ was due to operator overloading and how basic, seemingly native things like + can actually do a lot of hidden stuff unknown to the programmer. He must have softened on this since Rust offers the same facilities for operator overloading.

https://doc.rust-lang.org/stable/rust-by-example/trait/ops.h...

Operator overloading in Rust is less flexible than in C++, so there are fewer possibilities to mess it up.

Overloading is done indirectly via specific named traits which enforce method signatures, invariants, immutability rules. Assignments and moves can't be overloaded. Borrow checker limits what indexing and dereferencing overloads can do (hardly anything beyond pointer arithmetic on immutable data). Comparison operators can't be overloaded separately and can't return arbitrary values (like C++ spaceship operator). Generic code has to explicitly list what overloads it accepts (like C++ concepts), so even if you create a bizarre overload, it won't be used in generic code.

Linus’s point was also that C++ makes extensive use of function/method name overloading (is polymorphism) and this can make code hard to read. Not only is this not possible in C but the feature tends to be overused in C++.
Rust generally uses function/method polymorphism based on traits (aka type classes), that's far less prone to overuse and abuse than overloading in C++.
Is this form of polymorphism done at runtime and thus incurs a similar overhead to the C++ virtual?
There are two ways of doing it. The way most people use most of the time does not, it's statically dispatched. The other way is dynamically dispatched, though there are some differences from the way that C++ virtual works. They should be roughly the same in that case, though.
It depends, you have access to both capabilities. By default if you're only dealing with an impld trait then it will use static dispatch. If you are passing around that same object as a trait objects, it will use dynamic dispatch and you can also impl Traits on other traits, which are always used as trait objects (vtable) but that have some restrictions on what they can look like. If you rely on the Deref trait to make it look like you have inheritance (but in reality it is composition) it will be the same as the later using dynamic dispatch.
You can pick whether you want to do this at run-time or compile-time. The default is compile-time.
> Not only is this not possible in C ...

There are lots of object systems in C that have polymorphism via function pointers.

The linux kernel is full of those
I agree with this critique, but a good IDE helps, as does lint rules preventing egregious misuses (or even outlawing operator overloading entirely). As one example, many Java/C# linters prevent the use of non-curly-braced single line control statements entirely. The language allows them, but many codebases do not.
Could you give me a pointer to a discussion of type soudness in Rust? I recently watched perhaps 3 years old video about Rust where Simon Peyton-Jones asked about this, and Niko Matsakis answered it was ongoing work back then.

Couldn't find anything proper by googling.

See the work of Iris[1] project. It's open-source[2] and based on Coq, see Rust-related work[3] in particular.

[1] https://iris-project.org/

[2] https://gitlab.mpi-sws.org/iris/iris/

[3] https://gitlab.mpi-sws.org/iris/lambda-rust

Linus nowadays also uses Qt, so.
I would assume he sees difference between requirements for kernel code and a dive tracking GUI.