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by plus
2168 days ago
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What I'm saying is true -- if the initial state is chosen to be a superposition of states, then the time-dependent Schrodinger equation enables one to simulate the time evolution of the electron density. > thus, the "change" in the simulation posted here would be uninteresting since it would just correspond to clicking a different eigenstate in the top right! That is a drastic oversimplification of reality. Spontaneous emission of a photon is not instantaneous. It is still possible to simulate the time-evolution of this process. |
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what does the wave equation of the electron in a hydrogen atom look like during "spontaneous" emission of a photon? i don't think anyone has any idea.
i'm talking about something entirely separate from a linear combination of two energy eigenstates. i'm not saying take
\psi = \sin{\theta} \psi_1 + \cos{\theta} \psi_2
where \psi_1 and \psi_2 are eigenstates of the hydrogen atom hamiltonian and simulate it. i'm saying there is a phenomenon that i'm pretty sure wouldn't be adequately modelled by a smooth function.
edit: add explanation of \psi_1 and \psi_2