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by mb7733
2213 days ago
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I don't think xTx is is a great example for the demonstration of matrix calculus techniques, because it is a scalar. So, by definition, its derivative with respect to a vector v is going to be the gradient -- a vector of that scalar differentiated by each component of v. This is such a simple case it's not really necessary to introduce matrix calculus at all. It's when you take derivatives of vectors & matrices by other vectors & matrices that things get "interesting". |
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