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by dependenttypes 2216 days ago
> in a lazy language, you can certainly say:

Not in haskell. Which language do you specifically have in mind?
1 comments
tome 2216 days ago
Yes indeed in Haskell. You have enable RecursiveDo for that particular example to work. I'm not sure why ferzul chose a recursive monadic computation when

    let { x = 0:y; y = 0:x } in x
seems to demonstrate the same thing.
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