[gandercrews]

nah its pretty straightforward w/ higher order fns.

one of many possible solutions:

          {(1○⍺)>2○⍵} {(⍹ ⍵)/⍨⍵ ⍶ ⍹ ⍵} {⍵*2} {⍵/⍨2|⍵}⍳50
    1 9 49 225 361 441 625 1089 1521 1681 2025 2209

[eesmith]

Oh, sorry, I was too clever by half. I should have been more specific - hard to pull off in Panda.

Thanks for an APL solution in any case!