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cokernel_hacker
2241 days ago
Interesting. One issue is treatment of 1 / -inf. This would be -0 in traditional IEEE 754 but would now be +0 IIUC.
This would imply that 1 / (1 / -inf) would now be +inf instead of -inf.
1 comments
thechao
2240 days ago
0 is unsigned. I would reject 1/inf — it would be NAN. If the user wants to play silly games with derivatives, computer algebra systems are that way: —>.
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piadodjanho
2240 days ago
NaN is NaR (not a real) in posit notation.
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