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by a1369209993
2251 days ago
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> that UB represents a waiver of the Standard's jurisdiction for the purpose of allowing implementations to best serve their intended purposes? This won't work because defective implementations will just claim that their intended purpose is to do [whatever emergent behaviour that implementation produces], or to generate the fastest code possible regardless of whether that code bears any relation to what the programmer asked for. > As a simple example, instead of saying "a compiler may assume that all loops with non-constant conditions will terminate" This is actually completely unneeded, even for optimisation. If a side effect can be hoisted out of a loop at all, it can be hoisted regardless of whether the loop terminates. If the code (called from) inside the loop can (legally) observe the side effect, then it can't be hoisted even if the loop does always terminate. If code outside the loop observes the side effect, then either the loop terminates (and whatever lets you hoist terminating-loop side effects applies) or the code outside the loop is never executed (and thus can't observe any side effects, correct or incorrect). |
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I would have no qualm with the way clang and gcc process various constructs if they were to explicitly state that its maintainers make no effort to make their optimizer suitable for any tasks involving the receipt of untrustworthy input. Instead, however, they claim that their optimizers are suitable for general-purpose use, despite the fact that their behavior isn't reliably suitable for many common purposes.
> This is actually completely unneeded, even for optimisation.
Consider the following function:
Suppose the function is passed a value of "x" which would get caught in a cycle that never hits zero or one, but "mode" is 1. If the code is processed by performing every individual step in order, the function would never return. The rule in C11 is designed to avoid requiring that generated code compute the value of x when its only possible effect on the program's execution would be to prevent the execution of code that doesn't depend on its value.Suppose the most important requirement that function test() must meet is that it must never return 1 unless mode is 1, or the iteration on x would yield 1 before it yields zero; returning 1 in any other cases would cause the computer's speaker to start playing Barney's "I love you" song, and while looping endlessly would be irksome, it would be less bad than Barney's singing. If a compiler determines that slow_function_no_side_effects() will never return an even number, should it be entitled to generate code that will return 1 when mode is zero, without regard for whether the loop actually completes?
I would think it reasonable for a compiler to defer/skip the computation of x in cases where mode is 1, or for a compiler that can tell that "x" will never be an even number to generate code that, after ensuring that the loop will actually terminate, would unconditionally return 1. Requiring that the programmer write extra code to ensure that the function not return 1 in cases where mode is zero but the loop doesn't terminate would defeat the purpose of "optimization".