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by DougGwyn
2247 days ago
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The argument "0" is not automatically converted to the right type unless there is a prototype in scope. It isn't as important in this case because it is highly likely that the appropriate prototype has been #included, but it is a bigger deal if we're dealing with arguments for a variadic function. Anyway, it's good to be reminded what the declared types are. |
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You said the types were corrected, you didn’t say you were reminding about the declaration types. The types were correct from the start.