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by gnulinux
2262 days ago
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Currently in the US ~85% of tests turn negative. If sample turned positive you'd perform 10% more tests (1 extra test for each 10 tests) i.e. x1.1. If it turned negative you'd perform 10% the tests you'd normally perform without this scheme i.e. x0.1. In this case .85 of tests would be .1 of what they're now. The rest of .15 will be 1.1 of what they're now. So if US did this, they would be testing ~x.3 of their current testing. This seems huge. Can someone check my math please. |
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The general formula is (r^x) * (1/x) + (1 - r^x) * (1 + 1/x), where r is the percentage of negative tests and x is the number to mix.
With an 85% negative rate, it's more beneficial to mix 3 tests at a time for 0.72 tests per sample. (2 samples gives 0.78 tests, 4 gives 0.73) As more samples come back negative it becomes more advantageous to mix more, but you shouldn't mix 10 tests at a time (as opposed to 9) till you get to about a 96% negative rate, at which point you're running 0.44 tests per sample.
Edit: The binary search algorithm mentioned elsewhere would probably be more optimal, but I'm gonna do my day job instead of figuring out the dynamics of that one.