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by dmethvin 5587 days ago
javascript: void $('img').each(function(i,img) { var $i = $(img), w = $i.width(), h = $i.height(); if ( w && h ) img.src = 'http://placekitten.com/+w+/+h;});

Paste that in foxnews.com!

3 comments

syntax error, this should work;

    javascript:(function(){$('img').each(function(i,img){var $i = $(img), w = $i.width(), h = $i.height(); if ( w && h ){img.src = 'http://placekitten.com/'+w+'/'+h;}});})()
Hah!