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by nixpulvis 2281 days ago
Wait, ignoring firmware... you need to have some charge in order to charge with USB-C? Couldn't it use the lowest power modes until it has enough juice to communicate? This seems like a serious flaw with USB PD.
4 comments

That seems to be an implementation flaw. USB-C provides 5V by default with no negotiation which should be enough to power the controller and allow it to negotiate a higher voltage.
> USB-C provides 5V by default with no negotiation

Just to be pedantic, USB-C does need negotiation before it provides 5V, but that negotiation is just a pair of resistors of a specific value.

(Since the USB-C cable is symmetric, this negotiation is necessary to decide which end will provide the power. One end has both resistors wired as a pull-down, and the other end has both resistors wired as a pull-up. The end with both resistors wired as a pull-up will initially provide the 5V power.)

I routinely run my chromebook out completely out of battery charge, and it never has any issue charging with USB-C.
This is inaccurate, the Lemur Pro supports charging through USB-C with a dead battery.
Go long enough and even your minimal charge is exhausted
Then how can Macs be charged if they are fully exhausted?
I have no idea. Maybe they can't, but we won't find out for 5 years when someone brings one out of a closet. Maybe there is enough current leakage when in non charging mode for them to run that much electronics.