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by byte1918
2287 days ago
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No. Everything is 0s and 1s after all. Take for eg. a byte. It has 8 bits and by permutating all the 0s and 1s you end up with all the possible values of a signed byte; all the numbers -128 to 127. So now, if you were to copy a byte from a random memory location that byte will just contain a permutation of 0s and 1s which when interpreted as a signed int, will simply contain a number between -128 and 127. |
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