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by dmos62 2292 days ago
Counter question. How to calculate how many tries it would take to reach a specific probability for an outcome? For example, how many times do I have to roll the dice to have 90% chance of death? Due to my field of work, I'd solve everything by bruteforce, but I wonder what a more elegant solution could be.
1 comments

Just solve the equation above.

0.99^n = (1-0.9)

n*log(0.99) = log(0.1)

n = log(0.1)/log(0.99) = ~229