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by phkahler 2310 days ago
Yeah, I thought the electrical output seemed fishy too. Why are the electrons stripped from the helium? And is that actually due to the energy of the fusion reaction? And how much of the fusion energy is left after?

These are IMO the fundamental questions.

2 comments

> Why are the electrons stripped from the helium?

Hydrogen + Boron -> 3×Helium + energy

The energy is mostly 2900keV kinetic energy for each Helium ion i.e. the He ions just fuck off really fast and leave the elections behind.

If a He ions hits H atoms a couple of times, the second H hit has just the right energy to then hit another Boron and create an an avalanche of reactions. https://aip.scitation.org/na101/home/literatum/publisher/aip...

>> If a He ions hits H atoms a couple of times, the second H hit has just the right energy to then hit another Boron and create an an avalanche of reactions. https://aip.scitation.org/na101/home/literatum/publisher/aip....

Well that's frightening.

Only the helium nucleus is formed as part of the fusion reaction, so it starts off being positively charged, and not later stripped of its electrons. That, in principle, creates a current which can be used almost directly.
Well, it creates a region in space with a high charge density that can be accelerated to a plate that has a voltage applied to it which it bumps into which then causes a current.

Importantly, this doesn't have to happen in the reactor vessel. The charged gas can be pumped somewhere else.

It does have to happen in the reactor vessel. It's not just that it's a charged gas. It's that it's a charged gas which is exploding with almost 300 kWh of energy per shot.