|
|
|
|
|
|
by petrogradphilos
2323 days ago
|
|
|
> Since 0 is about 25 standard deviations from the mean, the probability of seeing 0 heads is on the order of 10⁻¹³⁸. Note: the above figure comes from the normal approximation to the binomial, which loses accuracy towards the tails. The exact probability of seeing 0 heads is (1 - p)^n = (1 - 2⋅10⁻⁶)^(311⋅10⁶) ≈ 10⁻²⁷⁰ [1]. [1] https://www.wolframalpha.com/input/?i=%281+-+2+*+10%5E-6%29%... |
|
|