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by nanis
2398 days ago
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There are uncountably infinite real numbers and countably infinite rational numbers, so we cannot represent all of them using a {0, 1}^n where n is a finite number. No matter which numbers you can exactly represent, there will always be uncountably many real numbers which are not exactly representable, and, conversely, the set of real numbers exactly representable using a finite number of bits will have measure zero. |
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