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by petschge
2430 days ago
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The split is actually much more uneven, and heavily on the side of kinetic energy. An orbit at 200 km altitude has an orbital velocity of 7.79 km/s. Potential energy is given by m * g * h (to good approximation, as h is much smaller than the Earth radius of 6300 km) and kinetic energy goes as 0.5 m v^2. Per unit mass (that appears identically in both energy forms) we have potential energy of g * h = 9.81 m / s^2 * 2e5 m = 1.96e6 m^2/s^2. For kinetic energy we find 0.5 * (7.79e3 m/s)^2 = 3e7 m^2/s^2. So only 6% of energy are potential energy, 94% are kinetic energy. For a relatively high orbit with 1500 km and 7.12 km/s the ratio becomes a more even 37% to 63%. If we include the extra 1.5km/s of delta-v that we loose to drag it becomes 28% to 72%. At the typical parameters of stage separation from the first stage the split is 3% to 97%. This is also why replacing the first stage by an airplane (that only gets you altitude, not that much speed) does buy you a lot less than you might think at first. We still need a rocket to go to space, even if you start 12km up. |
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What would happen if we were able to make it all the way up to space, vertically, but not gain any horizontal speed?