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by mjcohen 2468 days ago
The algorithm seems to be at least quadratic in the length. On a 2014 i7 Mac mini, (n, time(sec)) = (1000, 0.29), (2000, 1.65), (4000, 9.70), (8000, 58.42).
1 comments

I think this section on Wikipedia is relevant: https://en.wikipedia.org/wiki/Approximations_of_%CF%80#Grego...