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by gus_massa
2475 days ago
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The Area is not equal to the Entropy, it's only proportional. I think we agree about that. From there you deduct in the last paragraph that "Length = Entropy". I guess you want to use the radius or diameter of the black hole (and ignore a few more numerical constants). It doesn't make any sense, they aren't equal, they aren't proportional. The first error is that at some point you use that the volume is "equal" (proportional?) to the entropy, but this relation is wrong. The second error is that in "(Area x Length) = Entropy" you can replace Area by Length^2, and get Length^3 = Entropy. You say that "we can drop the invariants" and you drop the exponent 3, and you get "Length = Entropy", but now you are removing and exponent, not a multiplicative constant. So the "=" is not "equal", is not "proportional", it is only "somewhat related". |
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> It doesn't make any sense, they aren't equal, they aren't proportional.
That's not relevant. You increase one, you increase the other. [1]The equality symbol is not a literal equality. In a macro sense, it's a relationship that is directly correlated as opposed to equal in any sort of specific calculus.
> The first error is that at some point you use that the volume is "equal" (proportional?) to the entropy, but this relation is wrong.
You missed the point, which was initially:
> Here’s another way in which the analogy falls flat.
> So what do we make of all those thermodynamic relations that include volume, like Boyle’s law
Callendar was making his core argument that the entropy of a black hole is not expressed as a function of volume in one sense - because there's an assumption of quantum mechanics that take over, as you say it's "wrong" following the unproven "black hole thermodynamics" models ... but in another sense (Bekenstein–Hawking) there is a paper describing how surface area is a function of entropy. So this looks like a dichotomy since the surface area (which can tell you the entropy) can tell you the volume of a sphere, but volume of a black hole sphere isn't used to correlate to the entropy...so there's a dichotomy that is related to breaking laws (equivalence doesn't mean anything and it's all nonsense). Basically there's an assumption that beyond the event horizon we assume that the rules of physics break down into something new, although the black holes (theoretically per Bekenstein–Hawking) exhibit what a classical physicist would expect. Why not treat the black hole as if it has entropy as per the classical physics models, since it exhibits that quality already and see what insights that yields, rather than a whole new branch of thermodynamics that are necessarily exotic theory?
> now you are removing and exponent, not a multiplicative constant
See [1]
I have rephrased the position and I think maybe you should have a talk with the originator (ccallender@ucsd.edu) if you are still confused.