Would you care to explain this? When you mention tiling an octahedron with hexagons, the first thing I imagine is a truncated octahedron, which is composed of hexagons and squares.
You can start with 4 hexagons, each one covering an octant and a third of the neighboring octants.
Or another way to say this: if you start with 4 hexagons, with each glued together with each other along two adjacent edges, and you add the appropriate folds, you can make an octahedron.
Then you can subdivide each of those starting hexagons into n hexagons for any of these numbers, https://oeis.org/A003136 (power-of-4 sizes may be the most convenient among these, so that the overall grid has 2^n by 2^n size)
Or another way to say this: if you start with 4 hexagons, with each glued together with each other along two adjacent edges, and you add the appropriate folds, you can make an octahedron.
Then you can subdivide each of those starting hexagons into n hexagons for any of these numbers, https://oeis.org/A003136 (power-of-4 sizes may be the most convenient among these, so that the overall grid has 2^n by 2^n size)