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by gjm11 2564 days ago
Unfortunately, if you spot that pattern then you will not guess the correct generalization. It seems that this may be a puzzle that's easier to solve if you aren't good at spotting easy things.
1 comments

Well tbh, it seems 2^k-1 does actually match the sequence as far as it is shown. Perhaps there is a proof that n=2^k-1 for the numbers where 2^n is divisible by (n+1). I'll have to see.