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by chipperyman573
2579 days ago
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If each person has half the chance of a normal person and since if either one are chosen then the other is chosen, wouldn't their odds be (1/2 + 1/2) = 1 unweighted chance of being selected? Multiplying the odds by 2 (making your chance 2/4) lets you use this analogy: If you had a bag with 2 marbles labeled 1, along with and one 2 and one 3 marble, your chance of drawing either a 2 or a 3 is the same as drawing the 1 marble. This still works if you add more marbles to the mix, as long as they're weighted to be pulled twice as often as the 2 or 3 marble. |
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