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by lucb1e 2604 days ago
But that hash is a regular, fast hash that takes like 1µs to compute right? Doesn't that get lost in network jitter? Wouldn't averaging the time it takes to run for(i=0;i<Math.pow(2,18);i++); over 10 runs be much more accurate? Or is this meant to spite the 0.01% of visitors that really try not to be tracked and have turned off javascript?
1 comments

> But that hash is a regular, fast hash that takes like 1µs to compute right?

They use SHA512 which is fast, but noticeable for large enough files.

> Or is this meant to spite the 0.01% of visitors that really try not to be tracked and have turned off javascript?

Yes, the point is that it works with blockers.