| You just did it again. Used specifics from one application to pessimistically (and wrongly) apply to the technology generally. Also, you keep assuming the 4 3000kW locomotives will be running flat out, which is a terrible assumption (and would cause a conventional locomotive to quickly deplete its fuel, if not destroy its engine). Here, I'll do it for you. Good Panasonic cells get about 250Wh/kg, or 0.9MJ/kg. Assume an electric-optimized locomotive would be able to achieve about half its weight in cells, with a useful energy density of 0.45MJ/kg. Assume about 1 locomotive for every 9 cars, and with each car weighing the same as each locomotive. So the whole train's effective energy density is 0.045MJ/kg. The "rolling resistance" of a typical train is about 0.002, conservatively. That is a weight of 1 kgf has a resistance of 0.002kgf. (EDIT: This is a good assumption that works up to 60mph, the speed limit of freight trains, but at the typical low average speed of freight trains, it's actually about half that value: https://slideplayer.com/slide/4696076/15/images/12/Freight+T... ) The range is thus just: (specific energy)/((rolling resistance) * gravity) or: 0.045MJ/kg/(.002 * 9.8m/s^2) = ~2300km. https://www.google.com/search?q=0.045MJ%2Fkg%2F.002/(9.8m%2F... That's enough to go from the center of the continental US to the coast on a single charge. (and from what I understand, 1 engine for every 9 cars is not uncommon) If we have one engine for every 4 cars, you can now cross the continental US on a single charge. But remember, the discussion was about multiple recharges per trip, so there's WAY more battery here than you actually need. And to just give an idea of the power available, 130 tons is a typical car laden weight. 65 tons of Panasonic cells gives you 16.25MWh of storage. Cells like that can discharge their cells about 12 minutes. Lets make it 30 minutes, conservatively. That gives a power at the cell level of 32500 kilowatts, ten times your 3000kW locomotive. Batteries are plenty powerful. (And the cost is offset easily in fuel costs, as long as the battery is given the usage of about one full cycle at least once a week.) You might point out energy requirements for braking and climbing hills. But remember that one of the greatest advantages of battery-electrics is regenerative braking. Most of the energy consumed in increasing elevation can be recovered on the way back down. (As far as costs go, the battery pack should--including the price of industrial electricity and typical costs for automotive batteries at scale--pay for itself in fuel cost savings in about 500 cycle-equivalents while the cells should last at least 1000... meaning the overall added cost is potentially negative... meaning it's a market opportunity.) |
