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by zaroth
2732 days ago
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I appreciated the rudimentary presentation of the capabilities and limitations of the machine and calling out the connectivity of the qubits versus a universal quantum machine which would have full connectivity between all the bits. I’d be curious is there a simple formula for calculating the “effective universal qubits” of the D-Wave? 2,048 indeed sounds like a lot of qubits based on my extremely limited knowledge of quantum, but with only ~6k connections versus fully connected which would be n(n-1)/2 = ~2mil is it just a marketing gimmick? Why is it useful to push the bit count so high if the connectivity is so limited? |
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In those architectures, the limited connectivity enforces usage of SWAP gates, which increases the circuit depth.
Circuit depth, with imperfect qubits and gates, is currently the limiting factor - we don't have practical error-correction for the chips of today's size. Hence one can only perform a certain number of operations before his computation decoheres and becomes useless.