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by jkravitz61
2743 days ago
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Think of it like this: You produce energy at an amortized cost of $X /MW.
You store energy efficiently (lithium batteries) at an amortized cost of $Y /MW back into the grid.
You store energy inefficiently (Malta?) at an amortized cost of $Z /MW back into the grid. If Z<< Y, then simply ramp up your input production and you are likely in the money. Also, I'm not sure what you mean by "Worse heat has fairly low energy density and cools over time"... energy density is not relevant at all when you have practically unlimited space to store power (GIANT) fields next to your solar/wind farms. |
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Energy density is more a problem of materials. If you start talking GW hours it’s ~1GW from a ~38 ft tall and 48 meter diameter tank, even at $1,000 per ton it adds up. On top of that you need steam turbines etc.