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The energy density really is abysmal, which is why the "lifting heavy things up" techinique of energy storage is essentially never discussed outside of pumped-storage. The problem is the linear relationship between the mass, the height, and the stored energy: energy = mass * height * gravitational-acceleration. gravitational-acceleration is fixed at the earth's surface to ~10m/s2 So taking an example of 1,000,000 tons lifted up 100 meters: energy = 1,000,000,000 (mass) * 100 (height) * 10 (gravity) = 1,000,000,000,000 Joules This looks like a lot, but really isn't. It's equal to ~278 MWh (megawatt hours), which means it can supply 278 MWs for one hour. 278 MWs is equivalent to one small power station. Note that the largest pumped-storage power station in the UK, which is of course constrained by exactly the same E = mgh formula, Dinorwig (https://en.wikipedia.org/wiki/Dinorwig_Power_Station) stores ~9,000 MWh. Another way to consider this is to calculate how much mass needs lifting 100m to supply the whole of a country for a day. As a very crude estimate the UK requires an average of about 30,000MW of electrical energy. Over a day this equals 30,000,000,000 * 24 3,600,000 Joules = 2.510^18 Joules per day. The mass required to be lifted up 100m to store this is 2.510^18 / (100 10) = 2.510^15 Kg = 2.510^12 tons = 2,500,000,000,000 tons. Which is many times more than the current global annual concrete production of 10,000,000,000 tons (ref: http://www.columbia.edu/cu/civileng/meyer/publications/publi...) |
So... where do I sign up?