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by mendelk
2883 days ago
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Pretty cool concept on Timo Becker's site[0] (linked in TFA), and I'm trying to figure out how it's accomplished. If memory serves, there's 6! = 720 distinct graphs. Was a custom illustration created for each of those? Either way, really nicely done IMHO. [0] https://timobecker.com/ |
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Is it incorrect? How do you get "6!" ?
720 custom doodles seems doable, 2520 seems a bit much, so I suspect my reasoning for 7!/2 is wrong :)
Edit : oh, I see how for all closed paths all 7 permutations are the same so we can divide by 7 for closed paths, but there are still the open paths... hmmm (still pondering)
Edit 2 : aaaah, got it, I did not notice he was always closing the path himself... tss that's cheating :)