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by CuriousCosmic
2887 days ago
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Now how about a more complex example? bdP = bdA / pow((1 + bdr / bdm), (bdm - bdt)); bdP = bdA.divide((ONE.add(bdr.divide(bdm))).pow(bdm.subtract(bdt))); Obviously the first is more transparent than the second and this isn't a particularly complicated equation. Mind you that this can be mostly mitigated by splitting up the equation but that can sometimes make solutions quite opaque comparatively. |
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