[Ar-Curunir]

> I'm not sure I understand the author's implication that the energy used in the past to calculate the current price is equivalent to the energy to verify the current price.

That's just what P = NP means: the cost to verify a solution is the same as the cost of finding one.

[lend000]

Yes, but how the author relates that to a market's continuous price calculations is beyond me.

[babypistol]

In my opinion P = NP does not mean that. There still might be a big polynomial difference between verifying a solution and finding one.

[Ar-Curunir]

Of course, the concrete costs can be different; I was talking asymptotically :)

[babypistol]

Well that's the problem, man.

And asymptotically is not the right word either, because n^3 is asymptotically different from n^2. You probably meant poly-time reducible, whichs is quite different from "the same".