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by dahart
2954 days ago
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> There is no way to tell Python(CPython anyway) in which memory space you would it to create that object. Ah right, that's because all objects are heap-allocated. You choose heap by using an object for the stack, and rewriting your recursion to use (superficially) iterative code. You can choose stack allocation instead by using regular recursion: native function calls with local variables. What you bring up is an interesting issue that can make recursion harder to understand in Python. Having local objects in the stack frame can cause both stack and heap allocation - pointers for the objects on the stack, and the object contents on the heap. Or, you might have global objects that aren't local to the recursive function call or the stack, in which case it's important to understand you're sharing data across function calls. Generally speaking, you probably don't want individual heap allocations in a recursive function, so it's best not to have local objects. At least performance-wise. |
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You can choose stack allocation instead by using regular recursion: native function calls with local variables."
I'm not following you.
I believe these would both result in the same thing in Python. Python gives you a reference to an object. That object is stored in a private heap "somewhere." That reference to the object that Python gave you is stored on the stack. The object that it points to lives in the heap. This should be the same for both of your examples. I'm not sure what you mean by "native function calls." I am not familiar this this term.