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by caraffle
2963 days ago
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I don't think it's the same. arr[n] and [arr]n works because brackets simply expand to * (arr + n) in the first case, * (n + arr) in the second. C++ dictates if a statement can be interpreted as a declaration, it will be (see "The most vexing parse"). Universal initialization was introduced to provide another way to ensure this doesn't happen. https://softwareengineering.stackexchange.com/questions/1336... |
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