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by owl57
2985 days ago
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I believe all these languages, if they use some arrow in lambda syntax (so, except Rust), use the same kind of arrow for pattern matching. It's an obvious syntax choice when lambda arguments also use the same destructuring syntax: why would anyone want to remember which of those is `[x,y]->x+y` and which is `[x,y]=>x+y`? |
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