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by AdamWynne 5774 days ago
Seeing I wasn't using it, I thought I might hint to the optimiser that it could optimise it away. But now that you mention it, the argv should have been const char * const
1 comments

The optimizer is quite able to recognize that a variable is unused. :-)

In fact, if you compile that code with warnings turned on, you'll get a "variable is not used" warning -- which most style guides say should be silenced by adding the following line to the start of your function:

  (void)argc; /* UNUSED */