Hacker News new | ask | show | jobs
by jovial_cavalier 3080 days ago
> If an operation exceeds this limit, an insufficient significant bits signal "sNaN(isb)" would be raised.

What about for binary repeating decimals like 0.3? Wouldn't it always raise that signal?

1 comments

Presumably if you specify that you want more units of precision than are available, then yes. But if you say you only want 1 significant digit, then it can store it.