[V-2]

Yes it will be approaching 1, the same as for 10^24 coin tosses the number of heads would be approaching 50% (or 5*(10^23)).

[monktastic1]

Given the definition of "expected value," it is identically 1 (as opposed to merely "approaching it"). Sorry, I'm not trying to be pedantic.

https://en.wikipedia.org/wiki/Expected_value

[V-2]

You're absolutely correct - not being a native English speaker, I read "expected value" as a common phrase, not a probability theory term. Thanks