[bilboa]

Apparently constexpr is like "inline". Just as the inline keyword doesn't actually guarantee that the compiler will inline a function, so constexpr doesn't require the compiler to precompute something, but rather just gives a hint to the compiler that you'd like it to if it can.

[mike_hock]

constexpr means you CAN use the function in a constant expression

inline means you CAN define a function in multiple translation units without violating ODR

no guarantees in the other direction

[andrepd]

Gotcha, I think I understood it.