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by dahart
3179 days ago
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Right from that article you linked: "A non-self-intersecting continuous curve cannot fill the unit square because that will make the curve a homeomorphism from the unit interval onto the unit square (any continuous bijection from a compact space onto a Hausdorff space is a homeomorphism). But a unit square has no cut-point, and so cannot be homeomorphic to the unit interval, in which all points except the endpoints are cut-points." |
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Moreover OP's argument specifically proves too much, because space-filling curves (as described in the article) have a range with positive Borel measure.