|
|
|
|
|
by sqeaky
3258 days ago
|
|
> fee is based on the byte size of the transaction Aren'y all bitcoin transaction really close to the same size? The amount being transferred doesn't change the size an integer contain 1 and another container 1,000,000,000 take the same amount of space (32 or 64 bits) because the spec says so. I thought transaction fees encouraged miners to include your block in a transaction. |
|
If you're paying for your £3 coffee by transfering small amounts from many addresses, it's a big transaction.
Address fragmentation happens when your coins are distributed across many addresses, and can be caused by things like spending coins, because all transactions actually spend everything at an address and just route the "change" elsewhere. Buy two cups of coffee too close to each other and your next transaction is going to cost twice as much in fees, whoops!