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by bad_user
5830 days ago
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> The probability that they are both heads is 1/3. The probability they are both heads is 1/2. You're trying to formulate this as .... P(head AND head | one is a head) =
P(head AND head) / P(one is a head) =
1/4 * 4/3 = 4/12 = 1/3
But this is wrong ... you know that you have a head ... which makes ... P(one is a head) = 1 && P(head_a AND head_b) = P(head_a) = P(head_b)
1/3 would be the probability only on the first try (instead of stopping when you've got a head). |
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