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by Flenser
3280 days ago
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a = Appointment 1 start
A = Appointment 1 end
b = Appointment 2 start
B = Appointment 2 end
The only predicates are: a < A, b < BThe complete set of orderings are thus: aAbB - no overlap
bBaA - no overlap
abAB - partial overlap
baBA - partial overlap
abBA - complete overlap of one appointment inside the other
baAB - complete overlap of one appointment inside the other
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