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by hzhou321
3358 days ago
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Why should you get to choose your real number -- specifying more and more digits -- implies an un-exhaustive process, while I am not allowed to do the same? An unfair game will have unfair winners, how would it mean anything? If we both are allowed an un-exhaustive process of specifying what we have, this goes back to the counting game. As we never can finish, how does it make countable (or not)? |
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For any way of doing the mapping, there is a real number that the mapping misses. Alternative statement: "there is no such mapping that doesn't miss any of the reals".
This is shown because, given a mapping, I can find a real that the mapping misses.
When one says "for all x, there exists a y such that P(x,y)", the y is allowed to depend on the x.
That's what this is.
Why wouldn't your objection apply to the proof that the halting problem is uncomputable ? The program that the halting checker can't check is defined in terms of the halting checker. Why is that allowed? Because that is what the statement is saying. For any purported halting checker, there exists a program it doesn't decide the halting of.
Similarly here, for any purported bijection between the integers and the reals, there is a real that the purported bijection misses.
I don't know if you are using the word "countable" in the standard way, so I don't know what you mean by that last sentence.