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by mbid
3363 days ago
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I don't understand this. For a constructivist, "¬A" means "from A, falsity is derivable". You can derive falsity from the statement "there is a countable enumeration of the real numbers". A diagonal function given such an enumeration is constructively definable, and it is also constructively true that it is not equal to any of the enumerated ones (because 0 != 1 is true constructively). Thus, the diagonal is not enumerated all real numbers, but it also is by assumption, thus falsity. What does make real numbers weird when working constructively is that you cannot conclude |x| > 0 from x != 0. This means that 1 / x need not exist even if x != 0, so the real numbers do not form a field in the classical sense. If you don't trust me, maybe you'll trust wikipedia: https://en.wikipedia.org/wiki/Constructivism_(mathematics)#C.... |
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https://en.wikipedia.org/wiki/Cantor%27s_diagonal_argument#I...